![]() ![]() Another change is that since the ball bouncing off is considered in the -y direction, we would make 9.23sin40 to -9.23sin40. For the y component, we would carry out the same task, but instead, we would switch the cos out for a sin. So then we would subtract Vf-Vi and then multiply by the mass (mΔv remember) meaning that we should get -6.93x10^-5 or -6.93E-5. And since the ball is moving right on the plane, the question says that that is positive. To find the initial, we would just change the numbers accordingly. And with the triangle being a right triangle, we can simply do 9.23cos40. So we take 9.23 m/s and now have to find the x component in the triangle. To find Δpx, we have to use the mΔv formula, but to find Δv, we need to carry out trig function. The only way we can find the Δp is if we fine Δpx and Δpy and add them together (or subtract correct me if I'm wrong, but in this problem the way doesn't really matter, you'll see why). Starting off, we need to know what Δpx is and what Δpy is, because to find the force on the ball we can use the impulse-momentum theorem and say that FΔt=mΔv. The answer I got was slightly off by 10N but the process should be similar. No idea if this is relevant anymore but why not. ![]()
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